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GUJCET · Maths · Three Dimensional Geometry
The Cartesian equation of the line through the point \((5,-2,4)\) and which is parallel to the vector \(3 \hat{i}-2 \hat{j}+8 \hat{k}\) is ___________ .
- A \(\frac{x-5}{3}=\frac{y+2}{-2}=\frac{z-4}{8}\)
- B \(\frac{x+5}{-3}=\frac{y-2}{2}=\frac{z+4}{8}\)
- C \(\frac{x+5}{3}=\frac{y-2}{-2}=\frac{z+4}{8}\)
- D \(\frac{x-5}{-3}=\frac{y+2}{2}=\frac{z-4}{8}\)
Answer & Solution
Correct Answer
(A) \(\frac{x-5}{3}=\frac{y+2}{-2}=\frac{z-4}{8}\)
Step-by-step Solution
Detailed explanation
\( \frac{x-5}{3}=\frac{y-(-2)}{-2}=\frac{z-4}{8} \) \( \frac{x-5}{3}=\frac{y+2}{-2}=\frac{z-4}{8} \)
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