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GUJCET · Maths · Application of Integrals
The area bounded by the curve \(y=\sin x\) between \(x=-\pi / 2\) and \(x=\pi / 2\) is ___________ .
- A 4
- B 2
- C 3
- D 1
Answer & Solution
Correct Answer
(B) 2
Step-by-step Solution
Detailed explanation
\( A = \int_{-\pi/2}^{\pi/2} |\sin x| dx \) \( A = 2 \int_{0}^{\pi/2} \sin x dx \)
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