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GUJCET · Maths · Determinants
If the area of triangle is 3 sq. units whose vertices of triangle are \(A(1,3), B(0,0)\) and \(C(k, 0)\) then, \(k\) is equal to :
- A 2
- B -2
- C 0
- D \(\pm 2\)
Answer & Solution
Correct Answer
(D) \(\pm 2\)
Step-by-step Solution
Detailed explanation
\(Area = \frac{1}{2} |x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2)|\) \(3 = \frac{1}{2} |1(0 - 0) + 0(0 - 3) + k(3 - 0)|\)
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