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GUJCET · Maths · Three Dimensional Geometry
If the lines \(\frac{1-x}{3} = \frac{7y-14}{2p} = \frac{3-z}{-2}\) and \(\frac{7-7x}{3p} = \frac{y-5}{1} = \frac{6-z}{5}\) are perpendicular, then the value of \(p\) is ________.
- A \(\frac{35}{11}\)
- B \(\frac{11}{70}\)
- C \(\frac{70}{11}\)
- D \(-\frac{70}{11}\)
Answer & Solution
Correct Answer
(C) \(\frac{70}{11}\)
Step-by-step Solution
Detailed explanation
Direcciones de las líneas: \(L_1: \frac{x-1}{-3} = \frac{y-2}{2p/7} = \frac{z-3}{2} \implies \vec{d_1} = \left\langle -3, \frac{2p}{7}, 2 \right\rangle\)
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