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GUJCET · Physics · Moving Charges and Magnetism
Two Indentical coils having same number of turns and carrying equal current have common centre and their planes are at right angles to each other. What is the ratio of magnitude of the resultant magnetic field at the centre and magnetic field due to one of the coils at the centre ?
- A \(\sqrt{2}: 1\)
- B \(1: \sqrt{2}\)
- C \(2: 1\)
- D \(1: 1\)
Answer & Solution
Correct Answer
(A) \(\sqrt{2}: 1\)
Step-by-step Solution
Detailed explanation
A

The magnetic field induced by a coil at its centre.
\(B_1=\frac{\mu_0 I}{2 r}=B_2=B\)
Resultant magnetic field produc by two mutually perpendicu coils.
\(\begin{aligned} B _{\text {net }} & =\sqrt{ B _1^2+ B _2^2} \\ \therefore \quad B_{\text {net }} & =\sqrt{ B ^2+ B ^2} \\ \therefore \quad B_{\text {net }} & =\sqrt{2} B \\ \therefore \quad & \frac{ B _{\text {net }}}{ B }=\frac{\sqrt{2}}{1}\end{aligned}\)

The magnetic field induced by a coil at its centre.
\(B_1=\frac{\mu_0 I}{2 r}=B_2=B\)
Resultant magnetic field produc by two mutually perpendicu coils.
\(\begin{aligned} B _{\text {net }} & =\sqrt{ B _1^2+ B _2^2} \\ \therefore \quad B_{\text {net }} & =\sqrt{ B ^2+ B ^2} \\ \therefore \quad B_{\text {net }} & =\sqrt{2} B \\ \therefore \quad & \frac{ B _{\text {net }}}{ B }=\frac{\sqrt{2}}{1}\end{aligned}\)
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