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GUJCET · Maths · Determinants
If matrix \(A=\left[\begin{array}{lll}1 & 2 & 2 \\ 2 & 1 & 2 \\ 2 & 2 & 1\end{array}\right]\) then, Inverse of matrix \(A^{-1}\) is \(\frac{1}{5}\left[\begin{array}{ccc}-3 & 2 & 2 \\ 2 & -3 & \alpha \\ 2 & 2 & -3\end{array}\right]\) then, \(\alpha=\) _________
- A 3
- B 4
- C 2
- D -2
Answer & Solution
Correct Answer
(C) 2
Step-by-step Solution
Detailed explanation
\(A A^{-1} = I\) \(\frac{1}{5} \begin{bmatrix} 2 & 1 & 2 \end{bmatrix} \begin{bmatrix} 2 \\ \alpha \\ -3 \end{bmatrix} = 0\)
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