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GUJCET · Maths · Determinants

If matrix \(A=\left[\begin{array}{lll}1 & 2 & 2 \\ 2 & 1 & 2 \\ 2 & 2 & 1\end{array}\right]\) then, Inverse of matrix \(A^{-1}\) is \(\frac{1}{5}\left[\begin{array}{ccc}-3 & 2 & 2 \\ 2 & -3 & \alpha \\ 2 & 2 & -3\end{array}\right]\) then, \(\alpha=\) _________

  1. A 3
  2. B 4
  3. C 2
  4. D -2
Verified Solution

Answer & Solution

Correct Answer

(C) 2

Step-by-step Solution

Detailed explanation

\(A A^{-1} = I\) \(\frac{1}{5} \begin{bmatrix} 2 & 1 & 2 \end{bmatrix} \begin{bmatrix} 2 \\ \alpha \\ -3 \end{bmatrix} = 0\)