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GUJCET · Maths · Continuity and Differentiability
\(f\) is continuous at \(x=\frac{\pi}{2}\) where, \(f(x)=\left\{\begin{array}{cc}\frac{2 k \cos x}{\pi-2 x}, & x \neq \frac{\pi}{2} \\ 2024, & x=\frac{\pi}{2}\end{array}\right.\) then, the value of \(k\) is _________
- A 506
- B 1012
- C 2024
- D 4048
Answer & Solution
Correct Answer
(C) 2024
Step-by-step Solution
Detailed explanation
\( \lim_{x \to \frac{\pi}{2}} f(x) = f(\frac{\pi}{2}) \) \( \lim_{x \to \frac{\pi}{2}} \frac{2k \cos x}{\pi - 2x} = 2024 \)
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