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GUJCET · Physics · Dual Nature of Radiation and Matter
_________ is the wavelength of photon of energy 35 keV .
\(\left(h=6.625 \times 10^{-34} \mathrm{Js}, c=3 \times 10^{8} \mathrm{~m} / \mathrm{s}\right.\), \(\left.1 \mathrm{eV}=1.6 \times 10^{-19} \mathrm{~J}\right)\)
- A \(35 \times 10^{-12} \mathrm{~m}\)
- B \(35 \mathrm{~A}^{\circ}\)
- C 3.5 nm
- D \(3.5 \mathrm{~A}^{\circ}\)
Answer & Solution
Correct Answer
(A) \(35 \times 10^{-12} \mathrm{~m}\)
Step-by-step Solution
Detailed explanation
(Α) \(35 \times 10^{-12} \mathrm{~m}\)
from \(\mathrm{E}=\frac{h c}{\lambda}\)
\(
\begin{aligned}
& \lambda=\frac{6.625 \times 10^{-34} \times 3 \times 10^{8}}{35 \times 10^{3} \times 1.6 \times 10^{-19}} \\
& \lambda=0.35 \times 10^{-10} \mathrm{~m} \\
& \lambda=35 \times 10^{-12} \mathrm{~m}
\end{aligned}
\)
from \(\mathrm{E}=\frac{h c}{\lambda}\)
\(
\begin{aligned}
& \lambda=\frac{6.625 \times 10^{-34} \times 3 \times 10^{8}}{35 \times 10^{3} \times 1.6 \times 10^{-19}} \\
& \lambda=0.35 \times 10^{-10} \mathrm{~m} \\
& \lambda=35 \times 10^{-12} \mathrm{~m}
\end{aligned}
\)
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