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GUJCET · Physics · Current Electricity
Two electric bulbs are connected one by one across potential difference V. At that time power consumed in them are \(P_1\) and \(P_2\) respectively. Now if potential difference V is applied across series combination of these bulbs, what will be total power consumed ?
- A \(P_1+P_2\)
- B \(\sqrt{P_1 P_2}\)
- C \(\frac{P_1 P_2}{P_1+P_2}\)
- D \(P_1 P_2\)
Answer & Solution
Correct Answer
(C) \(\frac{P_1 P_2}{P_1+P_2}\)
Step-by-step Solution
Detailed explanation
(C)
for series connection
\(\frac{1}{P} =\frac{1}{P_1}+\frac{1}{P_2} \\\frac{1}{P} =\frac{P_2+P_1}{P_1 P_2} \\\therefore P=\frac{P_1 P_2}{P_1+P_2}\)
for series connection
\(\frac{1}{P} =\frac{1}{P_1}+\frac{1}{P_2} \\\frac{1}{P} =\frac{P_2+P_1}{P_1 P_2} \\\therefore P=\frac{P_1 P_2}{P_1+P_2}\)
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