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GUJCET · Maths · Three Dimensional Geometry

If lines \(\frac{x-3}{-3}=\frac{y-2}{2 k}=\frac{z-3}{2}\) and \(\frac{x-1}{3 k}=\frac{y-1}{1}=\frac{6-z}{5}\) are perpendicular to each other then, \(k=\) _________ .

  1. A \(\frac{7}{10}\)
  2. B \(-\frac{7}{10}\)
  3. C \(\frac{10}{7}\)
  4. D \(-\frac{10}{7}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(-\frac{10}{7}\)

Step-by-step Solution

Detailed explanation

Direction vectors: \( \vec{d_1} = \langle -3, 2k, 2 \rangle \), \( \vec{d_2} = \langle 3k, 1, -5 \rangle \). For perpendicular lines: \( \vec{d_1} \cdot \vec{d_2} = 0 \).