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GUJCET · Maths · Application of Integrals
The Area of the region bounded by curve \(y^2=4 x\) and line \(x=3\) is __________ sq. units.
- A 8
- B \(3 \sqrt{8}\)
- C \(8 \sqrt{3}\)
- D \(3 \sqrt{3}\)
Answer & Solution
Correct Answer
(C) \(8 \sqrt{3}\)
Step-by-step Solution
Detailed explanation
Intersection points: \(y^2 = 4(3) \implies y = \pm \sqrt{12} = \pm 2\sqrt{3}\) Area \(A = \int_{-2\sqrt{3}}^{2\sqrt{3}} (3 - \frac{y^2}{4}) dy\)
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