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GUJCET · Maths · Integrals
If \(\int \tan ^{-1} x d x= A x \cdot \tan ^{-1} x+ B \log \left(1+x^2\right)+ C\) then, \(A + B =\) ___________ .
- A -1
- B \(1 / 2\)
- C 1
- D \(-1 / 2\)
Answer & Solution
Correct Answer
(B) \(1 / 2\)
Step-by-step Solution
Detailed explanation
\(\int \tan ^{-1} x d x = x \tan ^{-1} x - \int x \cdot \frac{1}{1+x^2} d x\) \(= x \tan ^{-1} x - \frac{1}{2} \log \left(1+x^2\right) + C\)
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