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GUJCET · Physics · Electric Charges and Fields
Two point electric charges \(+10^{-8} C\) and \(-10^{-8} C\) are placed 0.1 m apart. Find the magnitude of total electric field at the centre of the line joining the two charges.
- A \(12.96 \times 10^4 NC ^{-1}\)
- B \(3.6 \times 10^4 NC ^{-1}\)
- C zero
- D \(7.2 \times 10^4 NC ^{-1}\)
Answer & Solution
Correct Answer
(D) \(7.2 \times 10^4 NC ^{-1}\)
Step-by-step Solution
Detailed explanation
(D)
Total Electric field.
\(\begin{array}{l}
E=E_{A}+E_{B} \\
E=\frac{k q}{r^2}+\frac{k q}{r^2} \\
E=2 \frac{k q}{r^2} \\
E=\frac{2 \times 9 \times 10^9 \times 10^{-8}}{(0.05)^2} \\
E=7.2 \times 10^4 NC^{-1}
\end{array}
\)
Total Electric field.
\(\begin{array}{l}
E=E_{A}+E_{B} \\
E=\frac{k q}{r^2}+\frac{k q}{r^2} \\
E=2 \frac{k q}{r^2} \\
E=\frac{2 \times 9 \times 10^9 \times 10^{-8}}{(0.05)^2} \\
E=7.2 \times 10^4 NC^{-1}
\end{array}
\)
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