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GUJCET · Maths · Application of Integrals
Area of the region bounded by the ellipse \(9 x^2+16 y^2=1\) in the first quadrant is _________ sq. units.
- A \(\frac{\pi}{48}\)
- B \(\frac{\pi}{12}\)
- C \(12 \pi\)
- D \(3 \pi\)
Answer & Solution
Correct Answer
(A) \(\frac{\pi}{48}\)
Step-by-step Solution
Detailed explanation
Equation of ellipse: \( \frac{x^2}{1/9} + \frac{y^2}{1/16} = 1 \) \( a = \sqrt{1/9} = 1/3 \), \( b = \sqrt{1/16} = 1/4 \)
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