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GUJCET · Maths · Continuity and Differentiability
If \(f(x)=1+x+x^2+\ldots \ldots \ldots . .+x^{1000}\) then, \(f^{\prime}(-1)=\) _________
- A -50
- B -500
- C -100
- D 500500
Answer & Solution
Correct Answer
(B) -500
Step-by-step Solution
Detailed explanation
\(f'(x) = 1+2x+3x^2+\ldots+1000x^{999}\) \(f'(-1) = 1+2(-1)+3(-1)^2+\ldots+1000(-1)^{999}\)
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