AP EAMCET · PHYSICS · Mechanical Properties of Fluids
Two spherical soap bubbles of radii \(r_1\) and \(r_2\) in vacuum combine under isothermal conditions. The resulting bubble has a radius equal to:
- A \(\frac{r_1+r_2}{2}\)
- B \(\frac{r_1 r_2}{r_1+r_2}\)
- C \(\sqrt{r_1 r_2}\)
- D \(\sqrt{r_1^2+r_2^2}\)
Answer & Solution
Correct Answer
(D) \(\sqrt{r_1^2+r_2^2}\)
Step-by-step Solution
Detailed explanation
Excess of pressure, inside the first bubble \(p_1=\frac{4 T}{r_1}\) Similarly, \(\quad p_2=\frac{4 T}{r_2}\) Let the radius of the large bubble be \(R\). Then, excess of pressure inside the large bubble, \(p=\frac{4 T}{R}\) Under isothermal condition, temperature remains…
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