AP EAMCET · Chemistry · d and f Block Elements
In neutral or faintly alkaline medium, \(\mathrm{MnO}_4^{-}\)oxidizes \(\mathrm{I}^{-}\)to iodate. What is the number of moles of \(\mathrm{KMnO}_4\) required to completely convert \(1 \mathrm{~L}\) of \(0.5 \mathrm{M} \mathrm{KI}\) to iodate?
- A \(0.5\)
- B \(4.0\)
- C \(2.0\)
- D \(1.0\)
Answer & Solution
Correct Answer
(D) \(1.0\)
Step-by-step Solution
Detailed explanation
Thus, according to the balanced equation, 1 mole of \(\mathrm{KI}\) or \(\mathrm{I}^{-}\)requires 2 moles of \(\mathrm{KMnO}_4\) or \(\mathrm{MnO}_4^{-}\). Therefore, \(1 \times 0.5=0.5\) moles of \(\mathrm{I}^{-}\)would require \(2 \times 0.5=1.0\) moles of \(\mathrm{KMnO}_4\).
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