AP EAMCET · PHYSICS · Units and Dimensions
In a system, unit of mass is \(A \mathrm{~kg}\), length is \(B \mathrm{~m}\) and time is \(C \mathrm{~s}\), then the value of \(10 \mathrm{~N}\) in this system is
- A \(10 A^{-1} B^{-1} C^{-2}\)
- B \(10 A^{-1} B^{-1} C^2\)
- C \(10 A B C^{-2}\)
- D \(5 A^{-1} B C^2\)
Answer & Solution
Correct Answer
(B) \(10 A^{-1} B^{-1} C^2\)
Step-by-step Solution
Detailed explanation
Using, \(\begin{aligned} \text {Using, } N_1 u_1 & =N_2 u_2 \\ 10 \mathrm{~kg} \frac{\mathrm{m}}{\mathrm{s}^2} & =N_2\left(\frac{A \cdot B}{C^2}\right) \\ \Rightarrow N_2 & =\frac{10 \cdot C^2}{A \cdot B} \\ & =10 A^{-1} B^{-1} C^2 \end{aligned}\) So, numerical value of…
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