AP EAMCET · PHYSICS · Work Power Energy
Two bodies A and B of masses 20 kg and 5 kg respectively are at rest. Due to the action of a force of 40 N separately, if the two bodies acquire equal kinetic energies in times \(t_A\) and \(t_B\) respectively, then \(t_A: t_B=\)
- A \(1: 2\)
- B \(2: 1\)
- C \(2: 5\)
- D \(5: 6\)
Answer & Solution
Correct Answer
(B) \(2: 1\)
Step-by-step Solution
Detailed explanation
\(K = \frac{F^2 t^2}{2m}\) \(\frac{F^2 t_A^2}{2m_A} = \frac{F^2 t_B^2}{2m_B}\) \(\frac{t_A^2}{m_A} = \frac{t_B^2}{m_B}\) \(\frac{t_A}{t_B} = \sqrt{\frac{m_A}{m_B}}\) \(\frac{t_A}{t_B} = \sqrt{\frac{20}{5}}\) \(\frac{t_A}{t_B} = \sqrt{4} = 2\) \(t_A: t_B = 2:1\)
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