AP EAMCET · Chemistry · Structure of Atom
If the radius of electron orbit in the excited state of hydrogen atom is \(476.1 \mathrm{pm}\), the energy of electron in that excited state in \(\mathrm{J}\) is (Radius and energy of electron in the first orbit of hydrogen atom are \(52.9 \mathrm{pm}\) and \(-2.18 \times 10^{-18} \mathrm{~J}\) respectively)
- A \(-2.42 \times 10^{-18}\)
- B \(-19.62 \times 10^{-18}\)
- C \(-2.42 \times 10^{-19}\)
- D \(-6.05 \times 10^{-19}\)
Answer & Solution
Correct Answer
(C) \(-2.42 \times 10^{-19}\)
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Given : Radius of excited state of hydrogen…
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