AP EAMCET · PHYSICS · Work Power Energy
A person of mass \(M=90 \mathrm{~kg}\) standing on a smooth horizontal plane of ice throws a body of mass \(m=10 \mathrm{~kg}\) horizontally on the same surface. If the distance between the person and body after \(10 \mathrm{~s}\) is \(10 \mathrm{~m}\), then the KE of the person (in \(\mathrm{J}\)) is
- A \(0.55 \mathrm{~J}\)
- B \(4.5 \mathrm{~J}\)
- C \(0.90 \mathrm{~J}\)
- D 0
Answer & Solution
Correct Answer
(A) \(0.55 \mathrm{~J}\)
Step-by-step Solution
Detailed explanation
According to the question body travels \(10 \mathrm{~m}\) in \(10 \mathrm{~s}\), hence its velocity is given as \(v=\frac{10 \mathrm{~m}}{10 \mathrm{~s}}=1 \mathrm{~m} / \mathrm{s}\) \(\therefore\) According to conservation of linear momentum. Initial total moment \(=\) Final…
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