AP EAMCET · PHYSICS · Current Electricity
In the circuit given below, if the bulb is to glow with maximum intensity, the value of ' \(R\) ' is
(neglect internal resistance of the cell)
- A \(1.25 \Omega\)
- B \(4.5 \Omega\)
- C \(6 \Omega\)
- D \(8.5 \Omega\)
Answer & Solution
Correct Answer
(A) \(1.25 \Omega\)
Step-by-step Solution
Detailed explanation
Resistance of bulb, \(R=\frac{V^2}{P}\) \(=\frac{(1.5)^2}{0.45}=5 \Omega\Resistance of bulb) \(P=i_1^2 R\) \(\begin{aligned} & 0.45=\mathrm{i}_1{ }^2 5 \\ & \mathrm{i}_1=0.3 \mathrm{~A}\end{aligned}\) Apply KVL, We have…
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