AP EAMCET · PHYSICS · Magnetic Effects of Current
A long straight wire of circular cross-section of radius ' \(a\) ' is carrying a steady current. The current is distributed uniformly across the cross-section of the wire. The ratio of the magnetic fields at points 0.5 a and 1.5 a from the centre of the wire is
- A \(1: 1\)
- B \(2: 3\)
- C \(1: 2\)
- D \(3: 4\)
Answer & Solution
Correct Answer
(D) \(3: 4\)
Step-by-step Solution
Detailed explanation
\(B_{0.5a} = \frac{\mu_0 I (0.5a)}{2\pi a^2} = \frac{0.5 \mu_0 I}{2\pi a}\) \(B_{1.5a} = \frac{\mu_0 I}{2\pi (1.5a)} = \frac{\mu_0 I}{3\pi a}\)…
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