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AP EAMCET · PHYSICS · Center of Mass Momentum and Collision

Two balls \(X(2 \mathrm{~kg})\) and \(Y(4 \mathrm{~kg})\) approach each other with equal speeds of \(10 \mathrm{~ms}^{-1}\). If the collision is perfectly elastic, then the new velocities of balls \(X\) and \(Y\) are respectively

  1. A \(\frac{50}{3} \mathrm{~ms}^{-1},-\frac{10}{3} \mathrm{~ms}^{-1}\)
  2. B \(-\frac{50}{3} \mathrm{~ms}^{-1},-\frac{10}{3} \mathrm{~ms}^{-1}\)
  3. C \(-\frac{50}{3} \mathrm{~ms}^{-1}, \frac{10}{3} \mathrm{~ms}^{-1}\)
  4. D \(\frac{50}{3} \mathrm{~ms}^{-1}, \frac{10}{3} \mathrm{~ms}^{-1}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(-\frac{50}{3} \mathrm{~ms}^{-1}, \frac{10}{3} \mathrm{~ms}^{-1}\)

Step-by-step Solution

Detailed explanation

Given, \(m_1=2 \mathrm{~kg}, m_2=4 \mathrm{~kg}\) \(v_1=v_2=10 \mathrm{~ms}^{-1}\) In perfectly elastic collision, momentum and kinetic energy is conserved. \(\therefore\) By conservation of momentum,…
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