AP EAMCET · PHYSICS · Nuclear Physics
The half life of a radioactive substance is 10 minutes. If \(n_1\) and \(n_2\) are the number of atoms decayed in 20 and 30 minutes respectively, then \(\mathrm{n}_1: \mathrm{n}_2=\)
- A \(7: 8\)
- B \(1: 2\)
- C \(6: 7\)
- D \(3: 4\)
Answer & Solution
Correct Answer
(C) \(6: 7\)
Step-by-step Solution
Detailed explanation
\(n(t) = N_0 \left[1 - \left(\frac{1}{2}\right)^{t/T_{1/2}}\right]\) \(n_1 = N_0 \left[1 - \left(\frac{1}{2}\right)^{20/10}\right] = N_0 \left[1 - \frac{1}{4}\right] = N_0 \left(\frac{3}{4}\right)\)…
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