AP EAMCET · PHYSICS · Mechanical Properties of Solids
Two wires of equal length and equal cross sectional areas are suspended as shown in the figure. Their Young's modulii are \(Y_1\) and \(Y_2\), respectively. The equivalent Young's modulus is
- A \(Y_1+Y_2\)
- B \(\frac{Y_1+Y_2}{2}\)
- C \(\frac{Y_1 Y_2}{Y_1+Y_2}\)
- D \(\sqrt{Y_1 Y_2}\)
Answer & Solution
Correct Answer
(B) \(\frac{Y_1+Y_2}{2}\)
Step-by-step Solution
Detailed explanation
Given, two wires have same length and equal cross-sectional area. i.e., \(l_1=l_2=l\) and \(A_1=A_2=A\) Suppose, \(m\) is the mass of the hanging load. From figure, \(2 T=m g\) i.e., \(T=\frac{m g}{2}\) Hence, stress on each wire \(=\frac{T}{A}=\frac{m g}{2 A}\)…
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