AP EAMCET · PHYSICS · Ray Optics
Magnifying power of an astronomical telescope for normal adjustment is 10 and length of the telescope is \(110 \mathrm{~cm}\). Magnifying power of the same telescope, when the image is formed at the near point is
- A 14
- B 18
- C 23
- D 26
Answer & Solution
Correct Answer
(A) 14
Step-by-step Solution
Detailed explanation
Magnifying power in normal adjustment, where \(f_{\mathcal{o}}\) and \(f_e\) are focal lengths of objective and eyepiece. \[ \begin{aligned} & \quad m=\frac{f_o}{f_e}=10 \\ & f_o=10 f_e \end{aligned} \] Given, tube length, \(f_o+f_e=110\)…
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