AP EAMCET · PHYSICS · Mechanical Properties of Solids
There is some change in length when a \(33000 \mathrm{~N}\) tensile force is applied on a steel rod of area of cross-section \(10^{-3} \mathrm{~m}^2\). The change of temperature required to produce the same elongation, if the steel rod is heated, is (The modulus of elasticity is \(3 \times 10^{11} \mathrm{~N} / \mathrm{m}^2\) and the coefficient of linear expansion of steel is \(\left.1.1 \times 10^{-5} /{ }^{\circ} \mathrm{C}\right)\).
- A \(20^{\circ} \mathrm{C}\)
- B \(15^{\circ} \mathrm{C}\)
- C \(10^{\circ} \mathrm{C}\)
- D \(0^{\circ} \mathrm{C}\)
Answer & Solution
Correct Answer
(C) \(10^{\circ} \mathrm{C}\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \text { Modulus of elasticity }=\frac{\text { Force }}{\text { Area }} \times \frac{l}{\Delta l} \\ & \qquad \begin{aligned} 3 \times 10^{11} & =\frac{33000}{10^{-3}} \times \frac{l}{\Delta l} \\ \frac{\Delta l}{l} & =\frac{33000}{10^{-3}} \times \frac{1}{3…
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