AP EAMCET · Maths · Straight Lines
If \(P(-1,0), Q(0,0)\) and \(R(3,3 \sqrt{3})\) are three points, then the equation of the bisector of the \(\lfloor{P Q R}\) is
- A \(x+\sqrt{3} y=0\)
- B \(\sqrt{3} x+y=0\)
- C \(x+\frac{\sqrt{3}}{2} y=0\)
- D \(\frac{\sqrt{3}}{2} x+y=0\)
Answer & Solution
Correct Answer
(B) \(\sqrt{3} x+y=0\)
Step-by-step Solution
Detailed explanation
\( \vec{QP} = (-1,0) \) \( \vec{QR} = (3, 3\sqrt{3}) \) \( \hat{u}_{QP} = \frac{(-1,0)}{\sqrt{(-1)^2+0^2}} = (-1,0) \) \( \hat{u}_{QR} = \frac{(3, 3\sqrt{3})}{\sqrt{3^2+(3\sqrt{3})^2}} = \frac{(3, 3\sqrt{3})}{6} = (\frac{1}{2}, \frac{\sqrt{3}}{2}) \) Direction vector of bisector…
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