ExamBro
ExamBro
AP EAMCET · Maths · Circle

Suppose the angle between the tangents drawn from \((0,0)\) to the circle \((x+\lambda)^2+(y+1)^2=\lambda^2\) is \(\frac{\pi}{2}\). Then, \(\lambda\) satisfies

  1. A \(\lambda^2=1\)
  2. B \(\lambda=0\)
  3. C \(\lambda^2=4\)
  4. D \(\lambda^2=9\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\lambda^2=1\)

Step-by-step Solution

Detailed explanation

\((x+\lambda)^2+(y+1)^2=\lambda^2\) \(\begin{aligned} & C \equiv(-\lambda,-1) r=\lambda \\ & \angle C O P=\frac{90^{\circ}}{2}=45^{\circ}\end{aligned}\) \(\begin{aligned} \therefore \quad O P & =C P=\lambda \\ O C & =\sqrt{\lambda^2+1}\end{aligned}\) In…