AP EAMCET · PHYSICS · Thermal Properties of Matter
A rod is found to be \(0.05 \mathrm{~cm}\) longer at \(40^{\circ} \mathrm{C}\) than it is at \(10^{\circ} \mathrm{C}\). The length of the rod at \(0^{\circ} \mathrm{C}\) is
(coefficient of linear expansion of the material of the rod \(\left.=1.5 \times 10^{-5}{ }^{\circ} \mathrm{C}^{-1}\right)\)
- A \(101.1 \mathrm{~cm}\)
- B \(120.2 \mathrm{~cm}\)
- C \(105.1 \mathrm{~cm}\)
- D \(111.1 \mathrm{~cm}\)
Answer & Solution
Correct Answer
(D) \(111.1 \mathrm{~cm}\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \mathrm{L} \text { at } 10^{\circ} \mathrm{C}=\mathrm{L}_0(1+10 \alpha) \\ & \mathrm{L} \text { at } 40^{\circ} \mathrm{C}=\mathrm{L}_0(1+40 \alpha) \\ & \mathrm{L}_{40^{\circ} \mathrm{C}}=0.05+\mathrm{L}_{10^{\circ} \mathrm{C}} \\ & \mathrm{L}_0+\mathrm{L}_0…
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