AP EAMCET · PHYSICS · Semiconductors
The voltage \(\mathrm{V}_0\) in the network shown is

- A \(\mathrm{V}_0=11.3 \mathrm{~V}\)
- B \(\mathrm{V}_0=9.8 \mathrm{~V}\)
- C \(\mathrm{V}_0=12.0 \mathrm{~V}\)
- D \(\mathrm{V}_0=0.7 \mathrm{~V}\)
Answer & Solution
Correct Answer
(A) \(\mathrm{V}_0=11.3 \mathrm{~V}\)
Step-by-step Solution
Detailed explanation
In the given circuit, Potential barrier of LED > Potential barrier of diode So, the equivalent circuit diagram is \(\begin{aligned} & \therefore \text { By KVL, } \\ & 12-0.7=V_0 \\ & \therefore V_0=11.3 \mathrm{~V} \end{aligned}\)
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