AP EAMCET · PHYSICS · Motion In Two Dimensions
A body is moving with a uniform speed of \(20 \mathrm{~ms}^{-1}\) on a horizontal circle. The change in velocity of the body in half revolution is
- A \(20 \mathrm{~ms}^{-1}\)
- B \(10 \mathrm{~ms}^{-1}\)
- C \(40 \mathrm{~ms}^{-1}\)
- D \(\frac{20}{\sqrt{2}} \mathrm{~ms}^{-1}\)
Answer & Solution
Correct Answer
(C) \(40 \mathrm{~ms}^{-1}\)
Step-by-step Solution
Detailed explanation
Speed of body, \(v=20 \mathrm{~m} / \mathrm{s}\) Change in velocity in half revolution \(\begin{aligned} & \Delta v=\vec{v}_2-\vec{v}_1=-v \hat{j}-v \hat{j}=-2 v \hat{j} \\ & |\Delta v|=2 v=2 \times 20=40 \mathrm{~m} / \mathrm{s}\end{aligned}\)
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