AP EAMCET · Maths · Application of Derivatives
The equation of tangent to the curve \(y=5 x^2-3 x+7\) at the point \((-1,4)\) is ......
- A \(13 x-y-9=0\)
- B \(13 x+y-9=0\)
- C \(13 x+y+9=0\)
- D \(13 x+2 y+5=0\)
Answer & Solution
Correct Answer
(C) \(13 x+y+9=0\)
Step-by-step Solution
Detailed explanation
Curve is, \(y=5 x^2-3 x+7\) Slope of tangent to curve at \((-1,4)\) is, \(m_T=\left.\frac{d y}{d x}\right|_{(-1,4)}=\left.(10 x-3)\right|_{x=-1}=-13\) Equation of tangent is,…
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