AP EAMCET · PHYSICS · Alternating Current
When an inductor \(L\) and a resistor \(R\) in series are connected across a \(12 \mathrm{~V}, 50 \mathrm{~Hz}\) supply, a current of 0.5 A flows in the circuit. The current differs in the phase from applied voltage by \(\frac{\pi}{3}\) radian. Then the value of \(R\) is
- A \(10 \Omega\)
- B \(3 \Omega\)
- C \(12 \Omega\)
- D \(15 \Omega\)
Answer & Solution
Correct Answer
(C) \(12 \Omega\)
Step-by-step Solution
Detailed explanation
Given situation following the figure below, Given for AC circuit, \(V_{\mathrm{rms}}=12 \mathrm{~V} \text {, }\) frequency, \(f=50 \mathrm{~Hz}\), current, \(\quad I=0.5 \mathrm{~A}\), phase difference, \(\phi=\frac{\pi}{3}\) \(\therefore\) Impedance of the AC circuit,…
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