AP EAMCET · PHYSICS · Motion In One Dimension
A body thrown vertically upwards from the ground reaches a maximum height ' \(H\) '. The ratio of the velocities of the body at heights \(\frac{3 \mathrm{H}}{4}\) and \(\frac{8 \mathrm{H}}{9}\) from the ground is
- A \(4: 9\)
- B \(27: 32\)
- C \(3: 2\)
- D \(3: 8\)
Answer & Solution
Correct Answer
(C) \(3: 2\)
Step-by-step Solution
Detailed explanation
Maximum height, \(\mathrm{H}=\frac{\mathrm{u}^2}{2 \mathrm{~g}} \Rightarrow \mathrm{u}=\sqrt{2 \mathrm{gH}}\) For \(\mathrm{h}_1=\frac{3 \mathrm{H}}{4}, \mathrm{v}_1^2=\mathrm{u}^2-2 \mathrm{gh}_1=(\sqrt{2 \mathrm{gH}})^2-2 \mathrm{~g}\left(\frac{3 \mathrm{H}}{4}\right)\)…
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