AP EAMCET · PHYSICS · Capacitance
The space between the plates of a parallel plate capacitor is filled with a mica sheet of thickness \(1 \times 10^{-3} \mathrm{~m}\) and a fiber sheet of thickness \(0.5 \times 10^{-3} \mathrm{~m}\). The dielectric constants of mica and fiber are 8 and 2.5 respectively. If the fiber breaks down at an electric field of \(6.4 \times 10^{-6} \mathrm{Vm}^{-1}\) then the maximum voltage that can be applied to the capacitor is
- A \(3400 \mathrm{~V}\)
- B \(5200 \mathrm{~V}\)
- C \(2700 \mathrm{~V}\)
- D \(4800 \mathrm{~V}\)
Answer & Solution
Correct Answer
(B) \(5200 \mathrm{~V}\)
Step-by-step Solution
Detailed explanation
Thickness, \(\mathrm{d}_1=1 \times 10^{-3} \mathrm{~m}\) and \(\mathrm{d}_2=0.5 \times 10^{-3} \mathrm{~m}\) Dielectric constant, \(\mathrm{K}_1=8\) and \(\mathrm{K}_2=2.5\) Electric field; \(\mathrm{E}_2=6.4 \times 10^{-6} \mathrm{~V} / \mathrm{m}\)…
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