AP EAMCET · PHYSICS · Mechanical Properties of Fluids
A tank of oil has height of \(4 \mathrm{~m}\) and density of \(850 \mathrm{~kg} \mathrm{~m}^{-3}\). The gauge pressure at the bottom of the tank is (1 atm \(=10^5 \mathrm{~Pa}\), Acceleration due to gravity \(=10 \mathrm{~ms}^{-2}\) )
- A \(34 \mathrm{kPa}\)
- B \(384 \mathrm{kPa}\)
- C \(284 \mathrm{kPa}\)
- D \(200 \mathrm{kPa}\)
Answer & Solution
Correct Answer
(A) \(34 \mathrm{kPa}\)
Step-by-step Solution
Detailed explanation
Tank of oil has height, \(h=4 \mathrm{~m}\) Density, \(\mathrm{P}=850 \mathrm{~kg} / \mathrm{m}^3\) Gauge pressure, \(P=\rho \mathrm{gh}\) \(=850 \times 10 \times 4=34 \mathrm{kPa}\)
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