AP EAMCET · PHYSICS · Electrostatics
A point charge ' \(q\) ' coulomb is placed at the centre of a cube of side length ' \(L\) '. Then the electric flux linked with each face of the cube is
- A \(\frac{q}{\epsilon_0}\)
- B \(\frac{q}{L^2 \in_0}\)
- C \(\frac{q}{6 L^2 \epsilon_0}\)
- D \(\frac{q}{6 \epsilon_0}\)
Answer & Solution
Correct Answer
(D) \(\frac{q}{6 \epsilon_0}\)
Step-by-step Solution
Detailed explanation
By Gauss's theorem, electric flux, \(\phi_{\text {cube }}=\frac{\mathrm{Q}_{\text {in }}}{\varepsilon_0}=\frac{\mathrm{q}}{\varepsilon_0} \Rightarrow 6 \phi_{\text {face }}=\frac{\mathrm{q}}{\varepsilon_0}\) \(\therefore \phi_{\text {face }}=\frac{q}{6 \varepsilon_0}\)
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