AP EAMCET · PHYSICS · Laws of Motion
The force required to stop a body of mass \(10 \mathrm{~kg}\) moving along a straight line path with a velocity of \(10 \mathrm{~ms}^{-1}\) in a time of \(10 \mathrm{~s}\) is
- A \(10 \mathrm{~N}\)
- B \(1000 \mathrm{~N}\)
- C \(100 \mathrm{~N}\)
- D \(1 \mathrm{~N}\)
Answer & Solution
Correct Answer
(A) \(10 \mathrm{~N}\)
Step-by-step Solution
Detailed explanation
Mass, \(\mathrm{m}=10 \mathrm{~kg}\) Initial velocity, \(u=10 \mathrm{~m} / \mathrm{s}\) Time, \(\mathrm{t}=10 \mathrm{sec}\) final velocity, \(\mathrm{V}=0\) using Newton's IInd law…
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