AP EAMCET · PHYSICS · Oscillations
The variation of potential energy of a harmonic oscillator is as shown in the figure. Then, find the spring constant.

- A \(1 \times 10^2 \mathrm{Nm}^{-1}\)
- B \(150 \mathrm{Nm}^{-1}\)
- C \(0.667 \times 10^2 \mathrm{Nm}^{-1}\)
- D \(3 \times 10^2 \mathrm{Nm}^{-1}\)
Answer & Solution
Correct Answer
(B) \(150 \mathrm{Nm}^{-1}\)
Step-by-step Solution
Detailed explanation
According to figure, when \(y=20 \mathrm{~mm}\) \(=2 \times 10^{-2} \mathrm{~m}\) then \(U_{\max }=0.04 \mathrm{~J}=4 \times 10^{-2} \mathrm{~J}\) When \(y=0\) then \(U_{\min }=0.01 \mathrm{~J}=1 \times 10^{-2} \mathrm{~J}\) \(\therefore\) The change in potential energy,…
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