AP EAMCET · PHYSICS · Motion In Two Dimensions
The relation between the horizontal displacement \(x\) (in metre) and the vertical displacement \(y\) (in metre) of a projectile is \(y=3 x-0.8 x^2\). The time of flight of the projectile is (Acceleration due to gravity \(=10 \mathrm{~ms}^{-2}\) ).
- A 1.5 s
- B 3 s
- C 2 s
- D 2.5 s
Answer & Solution
Correct Answer
(A) 1.5 s
Step-by-step Solution
Detailed explanation
For a projectile, \(y=3 x-0.8 x^2\)....(i) \(\begin{aligned} & \text { At } x=R, y=0 \\ & \therefore \quad 0=3 R-0.8 R^2 \\ & \Rightarrow \quad R(0.8 R-3)=0 \\ & \therefore \quad R=\frac{3}{0.8}=\frac{15}{4} m \end{aligned}\) Also,…
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