AP EAMCET · PHYSICS · Electromagnetic Induction
The initial rate of increase of current when a battery of emf \(6 \mathrm{~V}\) is connected in series with an inductance of \(2 \mathrm{H}\) and resistance of \(12 \Omega\) is
- A \(0.5 \mathrm{~A} \mathrm{~s}^{-1}\)
- B \(1 \mathrm{~A} \mathrm{~s}^{-1}\)
- C \(3 \mathrm{~A} \mathrm{~s}^{-1}\)
- D \(4 \mathrm{~A} \mathrm{~s}^{-1}\)
Answer & Solution
Correct Answer
(C) \(3 \mathrm{~A} \mathrm{~s}^{-1}\)
Step-by-step Solution
Detailed explanation
Given that, emf of battery, \(E=6 \mathrm{~V}\) Resistance, \(R=12 \Omega\) Inductance, \(L=2 \mathrm{H}\) We know that, the instantaneous current in the circuit containing \(R\) and \(L\) in series with battery of emf \(E\) is \[ I=I_0\left(1-e^{\frac{-R}{L} t}\right) \] where,…
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