AP EAMCET · Maths · Parabola
If \(5 x-2 y+k=0\) is a tangent to the parabola \(y^2=6 x\), then their point of contact is
- A \(\left(\frac{6}{5}, \frac{6}{5}\right)\)
- B \(\left(\frac{6}{5}, \frac{6}{25}\right)\)
- C \(\left(\frac{6}{25}, \frac{6}{5}\right)\)
- D \(\left(\frac{6}{25}, \frac{6}{25}\right)\)
Answer & Solution
Correct Answer
(C) \(\left(\frac{6}{25}, \frac{6}{5}\right)\)
Step-by-step Solution
Detailed explanation
Given curve \[ y^2=6 x \] difference w.r.t ' \(x\) ' \[ \Rightarrow \quad 2 y \frac{d y}{d x}=6 \] Given equation of tangent is \(5 x-2 y+k=0\)…
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