AP EAMCET · PHYSICS · Current Electricity
In a potentiometer experiment, when a cell in the secondary circuit is shunted by a resistance ' \(R\) ', balancing length is ' \(L_1\) '. On doubling the shunt resistance, balancing length increases to ' \(L_2\) '. Internal resistance of the cell is
- A \(\frac{2 \mathrm{R}\left(\mathrm{L}_2-\mathrm{L}_1\right)}{\mathrm{L}_1-2 \mathrm{~L}_2}\)
- B \(\frac{2 \mathrm{R}\left(\mathrm{L}_2-\mathrm{L}_1\right)}{\left(2 \mathrm{~L}_1-\mathrm{L}_2\right)}\)
- C \(\frac{\mathrm{R}\left(\mathrm{L}_2-\mathrm{L}_1\right)}{\mathrm{L}_1-2 \mathrm{~L}_2}\)
- D \(\frac{\mathrm{R}\left(\mathrm{L}_2-\mathrm{L}_1\right)}{\left(2 \mathrm{~L}_1-\mathrm{L}_2\right)}\)
Answer & Solution
Correct Answer
(B) \(\frac{2 \mathrm{R}\left(\mathrm{L}_2-\mathrm{L}_1\right)}{\left(2 \mathrm{~L}_1-\mathrm{L}_2\right)}\)
Step-by-step Solution
Detailed explanation
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