AP EAMCET · PHYSICS · Alternating Current
The number of turns in primary and secondary coils of a transformer is 50 and 200 respectively. If the current in the primary coil is \(4 \mathrm{~A}\), then the current in the secondary coil is
- A \(1 \mathrm{~A}\)
- B \(2 \mathrm{~A}\)
- C \(4 \mathrm{~A}\)
- D \(5 \mathrm{~A}\)
Answer & Solution
Correct Answer
(A) \(1 \mathrm{~A}\)
Step-by-step Solution
Detailed explanation
In a transformer \[ \begin{array}{rlrl} & & \frac{N_P}{N_S} & =\frac{I_S}{I_P} \\ & \frac{50}{200} & =\frac{I_S}{4} \\ & I_S & =1 \mathrm{~A} \end{array} \]
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