AP EAMCET · Maths · Straight Lines
The equation of the line passing through the point of intersection of the lines \(2 x+3 y+6=0,3 x-y-13=0\) and parallel to the line \(3 x-4 y+5=0\) is
- A \(3 x-4 y+75=0\)
- B \(3 x-4 y+15=0\)
- C \(3 x-4 y+25=0\)
- D \(3 x-4 y-25=0\)
Answer & Solution
Correct Answer
(D) \(3 x-4 y-25=0\)
Step-by-step Solution
Detailed explanation
Let \(L_1 \equiv 2 x+3 y+6=0\) \[ L_2 \equiv 3 x-y-13=0 \] Equation of line passing through the point of intersection. \[ \begin{array}{r} L_1+\lambda L_2=0 \\ (2 x+3 y+6)+\lambda(3 x-y-13)=0 \\ (2+3 \lambda) x+(3-\lambda) y+6-13 \lambda=0 \end{array} \] Which is parallel to the…
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