AP EAMCET · PHYSICS · Oscillations
An object is attached to the bottom of a light vertical spring and set vibrating. The maximum speed of the object is \(15 \mathrm{~cm} / \mathrm{s}\) and the period is 628 milli-seconds. The amplitude of the motion in cm is:
- A 3
- B 2
- C 1.5
- D 1
Answer & Solution
Correct Answer
(C) 1.5
Step-by-step Solution
Detailed explanation
\(v_{\max }=15 \mathrm{~cm} / \mathrm{s}=15 \times 10^{-2} \mathrm{~m} / \mathrm{s}\) \(T=628 \mathrm{~ms}=628 \times 10^{-3} \mathrm{~s}\) \(v_{\max }=A \omega \Rightarrow v_{\max }=A \times \frac{2 \pi}{T}\)…
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