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AP EAMCET · PHYSICS · Capacitance

A capacitor of capacitance \(2 \mu \mathrm{~F}\) is charged to 50 V and then disconected from the source. Later the gap between the plates of the capacitor is filled with a dielectric material. If the energy stored in the capacitor is decreased by \(25 \%\) of its initial value, then the dielectric constant of the dieletric material is

  1. A \(\frac{2}{3}\)
  2. B \(\frac{4}{3}\)
  3. C \(\frac{3}{4}\)
  4. D \(\frac{3}{2}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{4}{3}\)

Step-by-step Solution

Detailed explanation

\(U_f = U_i - 0.25 U_i = 0.75 U_i\) \(U_f = \frac{U_i}{k}\) \(\frac{U_i}{k} = 0.75 U_i\) \(k = \frac{1}{0.75} = \frac{4}{3}\)