AP EAMCET · PHYSICS · Dual Nature of Matter
The maximum wavelength of light which causes photoelectric emission from a photosensitive metal surface is \(\lambda_0\). Two light beams of wavelengths \(\frac{\lambda_0}{3}\) and \(\frac{\lambda_0}{9}\) incident on the metal surface. The ratio of the maximum velocities of the emitted photoelectrons is
- A \(3: 4\)
- B \(1: 3\)
- C \(1: 2\)
- D \(2: 3\)
Answer & Solution
Correct Answer
(C) \(1: 2\)
Step-by-step Solution
Detailed explanation
By Einstein's photoelectric equation, \(\begin{aligned} & \mathrm{E}=\phi_{\mathrm{o}}+\mathrm{K}_{\max } \\ & \Rightarrow \frac{\mathrm{hc}}{\lambda}=\frac{\mathrm{hc}}{\lambda_{\mathrm{o}}}=\frac{1}{2} \mathrm{mv}_{\max }^2 \end{aligned}\)…
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